Optimal. Leaf size=144 \[ -\frac{\sin (2 a+x (2 b-3 d)-3 c)}{16 (2 b-3 d)}-\frac{3 \sin (2 a+x (2 b-d)-c)}{16 (2 b-d)}-\frac{3 \sin (2 a+x (2 b+d)+c)}{16 (2 b+d)}-\frac{\sin (2 a+x (2 b+3 d)+3 c)}{16 (2 b+3 d)}+\frac{3 \sin (c+d x)}{8 d}+\frac{\sin (3 c+3 d x)}{24 d} \]
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Rubi [A] time = 0.0957972, antiderivative size = 144, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 2, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.118, Rules used = {4574, 2637} \[ -\frac{\sin (2 a+x (2 b-3 d)-3 c)}{16 (2 b-3 d)}-\frac{3 \sin (2 a+x (2 b-d)-c)}{16 (2 b-d)}-\frac{3 \sin (2 a+x (2 b+d)+c)}{16 (2 b+d)}-\frac{\sin (2 a+x (2 b+3 d)+3 c)}{16 (2 b+3 d)}+\frac{3 \sin (c+d x)}{8 d}+\frac{\sin (3 c+3 d x)}{24 d} \]
Antiderivative was successfully verified.
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Rule 4574
Rule 2637
Rubi steps
\begin{align*} \int \cos ^3(c+d x) \sin ^2(a+b x) \, dx &=\int \left (-\frac{1}{16} \cos (2 a-3 c+(2 b-3 d) x)-\frac{3}{16} \cos (2 a-c+(2 b-d) x)+\frac{3}{8} \cos (c+d x)+\frac{1}{8} \cos (3 c+3 d x)-\frac{3}{16} \cos (2 a+c+(2 b+d) x)-\frac{1}{16} \cos (2 a+3 c+(2 b+3 d) x)\right ) \, dx\\ &=-\left (\frac{1}{16} \int \cos (2 a-3 c+(2 b-3 d) x) \, dx\right )-\frac{1}{16} \int \cos (2 a+3 c+(2 b+3 d) x) \, dx+\frac{1}{8} \int \cos (3 c+3 d x) \, dx-\frac{3}{16} \int \cos (2 a-c+(2 b-d) x) \, dx-\frac{3}{16} \int \cos (2 a+c+(2 b+d) x) \, dx+\frac{3}{8} \int \cos (c+d x) \, dx\\ &=-\frac{\sin (2 a-3 c+(2 b-3 d) x)}{16 (2 b-3 d)}-\frac{3 \sin (2 a-c+(2 b-d) x)}{16 (2 b-d)}+\frac{3 \sin (c+d x)}{8 d}+\frac{\sin (3 c+3 d x)}{24 d}-\frac{3 \sin (2 a+c+(2 b+d) x)}{16 (2 b+d)}-\frac{\sin (2 a+3 c+(2 b+3 d) x)}{16 (2 b+3 d)}\\ \end{align*}
Mathematica [A] time = 1.82646, size = 158, normalized size = 1.1 \[ \frac{1}{48} \left (-\frac{3 \sin (2 a+2 b x-3 c-3 d x)}{2 b-3 d}-\frac{9 \sin (2 a+2 b x-c-d x)}{2 b-d}-\frac{9 \sin (2 a+2 b x+c+d x)}{2 b+d}-\frac{3 \sin (2 a+2 b x+3 c+3 d x)}{2 b+3 d}+\frac{18 \sin (c) \cos (d x)}{d}+\frac{2 \sin (3 c) \cos (3 d x)}{d}+\frac{18 \cos (c) \sin (d x)}{d}+\frac{2 \cos (3 c) \sin (3 d x)}{d}\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.036, size = 133, normalized size = 0.9 \begin{align*} -{\frac{\sin \left ( 2\,a-3\,c+ \left ( 2\,b-3\,d \right ) x \right ) }{32\,b-48\,d}}-{\frac{3\,\sin \left ( 2\,a-c+ \left ( 2\,b-d \right ) x \right ) }{32\,b-16\,d}}+{\frac{3\,\sin \left ( dx+c \right ) }{8\,d}}+{\frac{\sin \left ( 3\,dx+3\,c \right ) }{24\,d}}-{\frac{3\,\sin \left ( 2\,a+c+ \left ( 2\,b+d \right ) x \right ) }{32\,b+16\,d}}-{\frac{\sin \left ( 2\,a+3\,c+ \left ( 2\,b+3\,d \right ) x \right ) }{32\,b+48\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.41638, size = 1839, normalized size = 12.77 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.526663, size = 393, normalized size = 2.73 \begin{align*} \frac{6 \,{\left (6 \, b d^{3} \cos \left (b x + a\right ) \cos \left (d x + c\right ) -{\left (4 \, b^{3} d - b d^{3}\right )} \cos \left (b x + a\right ) \cos \left (d x + c\right )^{3}\right )} \sin \left (b x + a\right ) -{\left (18 \, d^{4} \cos \left (b x + a\right )^{2} - 16 \, b^{4} + 40 \, b^{2} d^{2} - 18 \, d^{4} -{\left (8 \, b^{4} - 38 \, b^{2} d^{2} + 9 \, d^{4} + 9 \,{\left (4 \, b^{2} d^{2} - d^{4}\right )} \cos \left (b x + a\right )^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{3 \,{\left (16 \, b^{4} d - 40 \, b^{2} d^{3} + 9 \, d^{5}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.14089, size = 174, normalized size = 1.21 \begin{align*} -\frac{\sin \left (2 \, b x + 3 \, d x + 2 \, a + 3 \, c\right )}{16 \,{\left (2 \, b + 3 \, d\right )}} - \frac{3 \, \sin \left (2 \, b x + d x + 2 \, a + c\right )}{16 \,{\left (2 \, b + d\right )}} - \frac{3 \, \sin \left (2 \, b x - d x + 2 \, a - c\right )}{16 \,{\left (2 \, b - d\right )}} - \frac{\sin \left (2 \, b x - 3 \, d x + 2 \, a - 3 \, c\right )}{16 \,{\left (2 \, b - 3 \, d\right )}} + \frac{\sin \left (3 \, d x + 3 \, c\right )}{24 \, d} + \frac{3 \, \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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